Find the m<1 and m<2. Justify each answer.
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m < 1 = 95 degrees ( alternate angles theorem of parallel lines)
m < 2 = 180 - 50 = 130 degrees ( internal angles theorem of parallel lines).
Answer:
[tex]\angle 1 = 225 \°\\\angle 2 = 130\°[/tex]
Step-by-step explanation:
In this problem we have to find the measure of angle 1 and angle 2.
So, we know by definition that all internal angles of a parallelogram must sum 360°. That is,
[tex]50\° + \angle 1 + \angle CBA + \angle 2 = 360\°[/tex]
However, by sum of angles, and by supplementary angles, we have
[tex]\angle CBA + 95\° = 180\°\\\angle CBA = 180\° - 95\°\\\angle CBA = 85\°[/tex]
Replacing this angle into the first expression, we have
[tex]50\° + \angle 1 + \angle CBA + \angle 2 = 360\°\\50\° + \angle 1 + 85\° + \angle 2 = 360\°\\\angle 1 + \angle 2 = 360\° - 85\° - 50\°\\\angle 1 + \angle 2 = 225\°[/tex]
We know by given that [tex]AB \parallel DC[/tex], that means BC and AD are transversals.
So, by alternate interior angles, we have
[tex]\angle 1 = 95\°[/tex]
That means,
[tex]\angle 1 + \angle 2 = 225\°\\95\° + \angle 2 = 225\°\\\angle 2 = 225\° - 95\°\\\angle 2 = 130\°[/tex]
Therefore,
[tex]\angle 1 = 225 \°\\\angle 2 = 130\°[/tex]