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Two jets leave an air base at the same time and travel in opposite directions. One jet travels 60 /mih faster than the other. If the two jets are 7848mi apart after 6 hours, what is the rate of each jet?

Respuesta :

slower jet speed is x

[tex]6 x + 6(x + 60) = 7848 \\ 12x + 360 = 7848 \\ x = 624[/tex]
so the two speeds are 624 and 684
shubhamchouhanvrVT

The speed of the slower jets and faster jets are 624 mi / Hr and 684 mi/hr respectively.

What is speed?

Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance.

Let the speed of a slower jet be represented as 'x'

Now Given:

one jet travels 60 mph slower than the other.

Hence Speed of a faster jet will be = x  +   60

Distance = 7848  miles

Time = 6 hrs

Now we know that;

Distance is equal to the product of speed and time.

Framing in the equation we get;

Distance = (Speed of Faster Jet + Speed of Slower jet) × Time.

Substituting the given values we get;

7848  =  ( x  +  x  +  60  )  6

7848  =  12x  +  360

x  =  624

Speed of slower jet = 624 miles/hr

Speed of faster jet = 624  +  60  =  684 miles/hr

Hence Speed of the Faster jet is 684 miles/hr and the speed of the slower jet is 624 miles/hr.

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