Graph the equation.
y=4x^2+8x+7

Answer:
See attached graph.
Step-by-step explanation:
To graph the quadratic, find the vertex using (-b/2a, f(-b/2a)).
The quadratic has values a=4, b =8, and c=7 from its standard form.
So -b/2a = -8/2(4) =-8/8 = -1.
f(-1) is 4(-1)^2 + 8(-1) + 7 = 4(1) -8+7 =4-8+7 = -4+7 = -3.
The vertex is the point (-1, -3).
To find another point, substitute x=0.
f(0) = 4(0)^2+8(0)+7 = 0+0+7 = 7.
Plot the point (0,7).