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The Ransin Sports Company has noted that the size of individual customer orders is normally distributed with a mean of $112 and a standard deviation of $9. If a soccer team of 11 players were to make the next batch of orders, what would be the standard error of the mean? 1.64 0.82 2.71 3.67

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JeanaShupp

Answer: 2.71

Step-by-step explanation:

We know that the formula to calculate the standard error is given by :-

[tex]S.E.=\dfrac{\sigma}{\sqrt{n}}[/tex], where [tex]\sigma[/tex] is the standard deviation and 'n' is the sample size.

Given : Standard deviation : [tex]\sigma=\$9[/tex]

Sample size : [tex]n=11[/tex]

Then , the standard error of the mean is given by :-

[tex]S.E.=\dfrac{9}{\sqrt{11}}=2.7136021012\approx2.71[/tex]

Hence, the standard error of the mean = 2.71

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