Answer:
25000 V
Explanation:
The formula for potential is
V = Kq/r
Potential at B due to the charge placed at origin O
V1 = K q / OB
[tex]V_{1}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{27}[/tex]
V1 = 10000 V
Potential at B due to the charge placed at A
V2 = K q / AB
[tex]V_{2}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{18}[/tex]
V2 = 15000 V
Total potential at B
V = V1 + V2 = 10000 + 15000 = 25000 V
