Answer:[tex]\frac{F}{2}[/tex]
Explanation:
Given
weight of Object is W
Buoyant Force [tex]F_b=F[/tex]
let the density of First Liquid is [tex]\rho [/tex]
volume of object [tex]=\frac{W}{\rho _0g}[/tex]
where [tex]\rho _0[/tex]=object density
thus buoyant Force in first Liquid is
[tex]F=\rho \times \frac{W}{\rho _0g}\times g=\frac{W\rho }{\rho _0}[/tex]
For Second Liquid
[tex]F'=\frac{\rho }{2}\times \frac{W}{\rho _0g}\times g=\frac{W\rho }{2\rho _0}[/tex]
[tex]F'=\frac{F}{2}[/tex]
