Answer:
F= 0.6321 N
Explanation:
Given
Area ,A= 14 cm²
Density ,ρ = 1.204 kg/m³
Velocity ,v= 50 m/s
Drag coefficient ,C=0.3
The drag force on the golf given as
[tex]F=\dfrac{1}{2}\rho CAv^2[/tex]
Now by putting the values
[tex]F=\dfrac{1}{2}\rho CAv^2[/tex]
[tex]F=\dfrac{1}{2}\times 0.3\times 1.204 \times (14\times 10^{-4})\times 50^2\ N[/tex]
F= 0.6321 N
Therefore force due to drag on the golf is 0.6321 N
