Could someone help me with this exercise?
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Answer:
Step-by-step explanation:
Let x represent the number of milliliters of 6.5% vinegar required. Then the total amount of acetic acid in the mix is ...
6.5%·x + 5%(200 -x) = 6%·200
1.5x = 200 . . . . . . . . . . . . . multiply by 100, subtract 1000
x = 200/1.5 = 133 1/3 . . . . mL of 6.5% vinegar
200-x = 66 2/3 . . . . . . . . . mL of 5% vinegar