Step-by-step explanation:
If the point is on the circle, then the distance from the center will be the same as the distance between (0,-3) and the center.
The distances are:
d = √((x₂ − x₁)² + (y₂ − y₁)²)
d = √((0 − 0)² + (-3 − 2)²)
d = √(0² + (-5)²)
d = 5
d = √((x₂ − x₁)² + (y₂ − y₁)²)
d = √((4 − 0)² + (-1 − 2)²)
d = √(4² + (-3)²)
d = 5
The distances are the same. So yes, the point is on the circle.
