Answer:
[tex]\Delta E=100[/tex]
Explanation:
To find the potential difference between [tex]x_{i}=2.0m[/tex] and [tex]x_{f}=3.0m[/tex], we just need to observe which vertical coordinates belong to these given values.
From the graph, we observe that [tex]x_{i}=2.0m[/tex] correspond to [tex]E_{i}=100[/tex], because they form the point [tex](2,100)[/tex] which is given in the graph.
With the same reasoning, we observe that [tex]E_{f}=200[/tex] corresponds to [tex]x_{f}=3.0m[/tex], because they both together form the points [tex](3,200)[/tex].
Now, the potential difference between the given distances, we just need to subtract
[tex]\Delta E=E_{f} -E_{i}=200-100=100[/tex]
Which also refers to the variation of the potential.
Therefore, the potential differential is [tex]\Delta E=100[/tex]
