Find the equation of the line that is perpendicular to y=-2/3x and contains the point (4,-8)
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Answer:
y = 3/2x -14
Step-by-step explanation:
y = -2/3 x
has a slope of -2/3
We want a line perpendicular
Take the negative reciprocal to find the slope
- (1 / -2/3)
3/2
The slope of a line perpendicular is 3/2
Using the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = 3/2x +b
Substitute a point into the equation
-8 = 3/2(4) +b
-8= 6+b
Subtract 6 from each side
-8-6 = b
y = 3/2x -14