Which equation describes the link passing through points (-5,-1) and (5,5) ?
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Answer: Choice D
y = (3/5)x + 2
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Explanation:
Find the slope
m = (y2-x1)/(x2-x1)
m = (5-(-1))/(5-(-5))
m = (5+1)/(5+5)
m = 6/10
m = 3/5
Now use point slope form and solve for y
y - y1 = m(x - x1)
y - (-1) = (3/5)(x - (-5))
y + 1 = (3/5)(x + 5)
y + 1 = (3/5)x + (3/5)*5
y+1 = (3/5)x + 3
y = (3/5)x + 3 - 1
y = (3/5)x + 2