Given :
Pilot sits 2.19 m from the center of rotation.
Horizontal centripetal acceleration is 65.8 m/s².
To Find :
The angular velocity of the pilot .
Solution :
We know, centripetal acceleration is given by :
[tex]a = \omega^2 r\\\\\omega = \sqrt{\dfrac{a }{r}}\\\\\omega = \sqrt{\dfrac{65.8 }{2.19}}\\\\\omega = 5.48\ s^{-1}[/tex]
Hence, this is the required solution.
