For the function f(x) = -4x^2 + 8x+8, find the slope of the tangent line at
X = -3.
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Answer:
Find the corresponding y-value to x=−3.
Substitute −3 in for x.
y=−4(−3)²+8(−3)+8
Simplify −4(−3)²+8(−3)+8
y=−36−24+8 => y=−52
Find the first derivative and evaluate at x=−3 and y=−52 to find the slope of the tangent line.
Plug the slope and point values into the point-slope formula and solve for y
y=32x+44
Step-by-step explanation: