Answer: Thus there are 88.4 g of calcium bromide.
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
Molar mass of = 40.1 (1)+ 2(79.9) = 199.9
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]0.442=\frac{x}{199.9}[/tex]
[tex]x=88.4g[/tex]
Thus there are 88.4 g of calcium bromide.
