Answer:
the pressure exerted at the base of the container is 490 N/m²
Explanation:
Given;
density of water, ρ = 1,000 kg/m³
base of the rectangular container, = 50 cm by 30 cm
height of water in the tank, h = 5 cm = 0.05 m
The pressure exerted at the base of the container is calculated as;
P = ρgh
where;
g is acceleration due to gravity = 9.8 m/s²
P = 1000 x 9.8 x 0.05
P = 490 N/m²
Therefore, the pressure exerted at the base of the container is 490 N/m²
