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Use trigonometric ratios to solve each right triangle. Be sure to rationalize the denominators when you write your answers.

Use trigonometric ratios to solve each right triangle Be sure to rationalize the denominators when you write your answers class=

Respuesta :

Answer:

[tex]sin(45)=\frac{AC}{AB} =\frac{AC}{12} \\AC=12\times sin(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}\\ cos(45)=\frac{CB}{AB} =\frac{CB}{12} \\CB=12\times cos(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}[/tex]

Step-by-step explanation:

[tex]sin(45)=\frac{AC}{AB} =\frac{AC}{12} \\AC=12\times sin(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}\\ cos(45)=\frac{CB}{AB} =\frac{CB}{12} \\CB=12\times cos(45)=12\times \frac{\sqrt{2}}{2}=6\sqrt{2}[/tex]

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