Answer:
20 m/s
Explanation:
First, we calculate for the acceleration down the incline using [tex]a = gsin\theta[/tex].
a = (9.80)sin(20°)
a = 3.35
Then, we use one of the kinematics equations, [tex]{v_{f}}^{2} = {v_{i}}^{2} + 2 a\Delta s[/tex].
[tex]v_{i}[/tex] = 0 m/s
a = 3.35
[tex]\Delta s[/tex] = 62 m
[tex]v_{f} = \sqrt{2(3.35)(62)}[/tex]
[tex]v_{f} =20.381 = 20 m/s[/tex]
