A ball rolls down a ramp for 5 seconds. It accelerated 3m/s2 until it reached 28 m/s. What was the ball’s initial velocity? (select the correct equation)
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Answer:
Option 4 is correct ,
Explanation:
By the question,
Time (t) = 5 sec
accelation (a) = 3m/s^2
final velocity (Vf) = 28m/s
we know that ,
[tex]a = \frac{vf - vi}{t} [/tex]
so, doing cross multiplication , we get:-
[tex]vf - vi = a \times t \\ vi = vf - a \times t \\ vi = 28 - (3 \times 5)[/tex]