Answer:
D
Step-by-step explanation:
There are 9 letters, which contains 2Qs, 3Ls and 4Bs.
If the 9 letters are distinct, the number of permutations they have will be 9!.
! is the factorial sign.
9! = 9*8*7*6*5*4*3*2*1
HOWEVER, we have some identical elements, so we need to get rid of the permutations of the same letters.
Thus we have:
[tex]\dfrac{9!}{2!*3!*4!} =\dfrac{9*8*7*6*5}{2*3*2*1} = \dfrac{9*4*7*5}{1} = 63*20=1260[/tex]
The answer is D
