Respuesta :

dexteright02
[tex] \frac{ \sqrt{3y} }{ \sqrt{x} } = \frac{ \sqrt{3x} * \sqrt{3y} }{ \sqrt{x} * \sqrt{x} } = \frac{ \sqrt{3x*3y} }{ (\sqrt{x})^2 } = \frac{ \sqrt{3^{2}*x*y} }{x} = \frac{ \sqrt{ 3^{2} }* \sqrt{x*y} }{x} = \frac{3* \sqrt{x*y} }{x} = \boxed{\frac{3 \sqrt{xy} }{x}} [/tex]