A side of the triangle below has been extended to form an exterior angle of 62°. Find the value of xx.
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Solution:
Note that:
Simplify the equation to find x.
Sum of interiors=exterior
[tex]\\ \rm\bull\rightarrowtail x+46=62[/tex]
[tex]\\ \rm\bull\rightarrowtail x=62-46[/tex]
[tex]\\ \rm\bull\rightarrowtail x=16[/tex]