I know that AC and DB intersect at point E what would be the 3 pairs of angles though? More explanation
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Solution;
From your drawing;
[tex]m\angle ADE=m\angle BCE(angles\text{ in the same segment are equal})[/tex][tex]m\angle DAE=m\angle CBE(angles\text{ in the same segment are equal})[/tex][tex]m\angle AED=m\angle BEC(vertically\text{ opposite angles are equal})[/tex]