Given data:
The expression for the volume is V=(kT)/P.
The given expression can be written as,
[tex]\begin{gathered} k\frac{T_1}{P_1}=k\frac{T_2}{P_2} \\ \frac{T_1}{P_1}=\frac{T_2}{P_2} \end{gathered}[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} \frac{84\text{ K}}{8kg/cm^2}=\frac{185\text{ K}}{P_2} \\ P_2=17.619kg/cm^2 \end{gathered}[/tex]Thus, the final pressure is 17.619 kg/cm^2.
