We can find the general term of this arithmetic sequence:
[tex]a_n=4000+(n-1)\cdot d[/tex]In this way, we have the following sequence for the first term:
[tex]a_{1=}4000+(1-1)\cdot100=4000[/tex]For the last term (the last month) (his monthly salary at the end of his training) is:
[tex]a_{12}=4000+(12-1)\cdot100\Rightarrow a_{12}=4000+11\cdot100\Rightarrow a^{}_{12}=5100[/tex]