2 KI + Pb(NO3)2 - Phl, + 2 KNO,how many moles of lead(II) iodide (Pbly) are produced from 6.0 mol of potassium iodide (KI)?number of moles:molTOOLS*10%
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Answer
3.0 mol
Explanation
Given:
Moles of KI = 6.0 mol
Chemical reaction:
What to find:
The moles of lead iodide (PbI₂) produced.
Step-by-step solution:
From the given balanced chemical reaction above;
2 mol KI produced 1 mol PbI₂,
so 6.0 mol KI will produce:
[tex]\frac{6.0\text{ }mol\text{ }KI\times1\text{ }mol\text{ }PbI_2}{2\text{ }mol\text{ }KI}=3.0\text{ }mol\text{ }PbI_2[/tex]The number of moles of PbI₂ produced = 3.0 mol