Suppose that a variable has a binomial distribution with n=18 and p=0.48 what is the expected value of the variable?
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Answer:
8.64
Explanation:
The expected value for a binomial distribution is equal to
E = np
Where n is the number of trials and p is the probability of success. In this case, n = 18 and p = 0.48. Then, the expected value is
E = (18)(0.48)
E = 8.64
Therefore, the answer is 8.64