We want to know the center and the radius of the circle:
[tex]x^2-2x+y^2=0[/tex]
We remember that the equation of a circle is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
In this case, we complete the square by adding 1 and substracting 1:
[tex]\begin{gathered} x^2-2x+1+y^2-1=0 \\ x^2-2x+1+y^2=1 \\ \text{Factoring the first three terms, we obtain:} \\ (x-1)^2+y^2=1 \end{gathered}[/tex]
This means that the center is the point (1,0), and:
[tex]\text{Radius: }\sqrt[]{1}=1[/tex]
