We are given the following function of distance in terms of time:
[tex]d=16t^2[/tex]Where:
[tex]\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}[/tex]We are asked to determine the time when the distance is 4ft. To do that we will solve for "t". First, we will divide both sides by 16:
[tex]\frac{d}{16}=t^2[/tex]Now, we take the square root to both sides:
[tex]\sqrt{\frac{d}{16}}=t[/tex]Simplifying we get:
[tex]\frac{1}{4}\sqrt{d}=t[/tex]Now, we substitute the value of the distance:
[tex]\frac{1}{4}\sqrt{4}=t[/tex]Solving the operations:
[tex]\begin{gathered} \frac{1}{2}=t \\ \\ 0.5=t \end{gathered}[/tex]Therefore, the time is 0.5
The same procedure is used to determine the time for 64 feet.
