Respuesta :

Answer: 8.1297x10^24 molecules

Calculations:

Balanced Reaction :

[tex]2Fe+3O_2\Rightarrow2Fe_2O_3[/tex]

1. by stoichiometry,

• 2 moles of Fe : 2 moles of iron (iii) oxide

• then 13.5 moles Fe : x

X = 13.5 *2 /2 = 13.5 moles of Fe

• This means that 13.5 mole of Fe2O3 will be produce.

2. Calculate number of molecules by Avogardo principles.

No. of molecules = Moles * Avogardo Number

[tex]\begin{gathered} Fe_2O_{3\text{ }}Molecules\text{ = 13.5 moles }\cdot6.022\cdot10^{23} \\ \text{=8.1297}\cdot10^{24} \end{gathered}[/tex]

• This means that there are 8.1297 x10^24molecules of Fe2O3 from 13.5 moles Fe.

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