SOLUTION
The function can be derived from the model
[tex]\begin{gathered} P=P_oe^{(\ln r)t^{}} \\ \\ r\text{ here represents 1 + 9 percent growth rate } \end{gathered}[/tex]
So the function becomes
[tex]P(t)=2000_{}e^{(\ln 1.09)t}[/tex]
So the fox population in 2008
2008 - 2000 = 8
So our t becomes 8
The population becomes
[tex]\begin{gathered} P=2000_{}e^{(\ln 1.09)t} \\ P=2000_{}e^{(\ln 1.09)\times8} \\ P=\text{ }2000_{}e^{0.086177\times8} \\ =2000_{}e^{0.6894} \\ =\text{ 3985.04} \end{gathered}[/tex]
So the Population = 3985
