Explanation:
The equation of formation of NO₂
1/2 N₂ (g) + O₂ (g) <----> NO₂ (g)
The equilibrium for the above reaction can be calculated using this equation:
Kc = [NO₂]/([N₂]^(1/2)*[O₂]) where the concentrations are the equilibrium concentrations.
According to the graph the concentration in the equilibrium of each compound is:
[NO₂] = 6 mol/L
[N₂] = 10 mol/L
[O₂] = 20 mol/L
If we replace these values in the given equation:
Kc = [NO₂]/([N₂]^(1/2)*[O₂])
Kc = (6 mol/L)/[(10 mol/L)^(1/2)*(20 mol/L)]
Kc = 0.095
Answer: Kc = 0.095
