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A glass jar contains 3 red, 13 green, 4 blue, and 8 yellow marbles. If a single marble is chosen at random from the jar, what is the probability of choosing a(a) red marble? (b) green marble? (c) blue marble?

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Solution

(a) red marble?

[tex]p=\frac{\text{red}}{\text{total}}=\frac{3}{3+13+4+8}=\frac{3}{28}[/tex]

(b) green marble?

[tex]p=\frac{\text{gren}}{\text{total}}=\frac{13}{3+13+4+8}=\frac{13}{28}[/tex]

(c) blue marble?​

[tex]p=\frac{\text{blue}}{\text{total}}=\frac{4}{3+13+4+8}=\frac{4}{28}[/tex]

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