Really need help with 11 and 12 just started learning this today and I don't quite understand it would really appreciate it
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11.
Given:
[tex]y=x^2[/tex]Differentiate with respect to x, we get
[tex]\frac{dy}{dx}=2x[/tex]The given point is (3,9)
Substitute x=3 in the derivative, we get
[tex]\frac{dy}{dx}=2\times\times3=6[/tex]Hence the slope is 3.
12.
Given:
[tex]y=x^2+4[/tex]Differentiate with respect to x, we get
[tex]\frac{dy}{dx}=2x+0[/tex]The given point is (0,4)
Substitute x=0 in the derivative, we get
[tex]\frac{dy}{dx}=2(0)+0=0[/tex]Hence the slope is 0.