A container holds 283 ml of chlorine gas (cl2. assuming that the gas sample is at stp, what is its mass?

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04-03-2017
Chemistry

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A container holds 283 ml of chlorine gas (cl2. assuming that the gas sample is at stp, what is its mass?

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dexteright02 dexteright02 · Answer 1 · 2017-03-04T19:32:02+01:00

Data:
STP means
T = 0ºC or 273 K
P = 1 atm
V = 283 mL = 0.283 L
R = 0.082 atm*L/mol*K

Formula: Find "n" moles

[tex]n = \frac{P*V}{R*T} [/tex]

Solving:

[tex]n = \frac{P*V}{R*T} [/tex]
[tex]n = \frac{1*0.283}{0.082*273}[/tex]
[tex]n = \frac{0.283}{22.3} [/tex]
[tex]\boxed{n \approx 0.01\;mol}[/tex]

Now find the mass
Knowing that the molar mass of [tex]Cl_{2}[/tex] = 71 g / mol

[tex]0.01\:\diagup\!\!\!\!\!\!mol* \frac{71\:grams}{1\:\diagup\!\!\!\!\!\!mol} = \boxed{\boxed{0.71\:grams\: Cl_{2} }}\end{array}}\qquad\quad\checkmark[/tex]