What is the equation of the line perpendicular to y=3x+2 that passes through the point (0, 2)?

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01-07-2017
Mathematics

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What is the equation of the line perpendicular to y=3x+2 that passes through the point (0, 2)?

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LAGRHA15 LAGRHA15 · Answer 1 · 2017-07-07T03:07:11+02:00

LAGRHA15 LAGRHA15

07-07-2017

The equation is y = -1/3x + 2.

Point Slope Form : y - y1 = m(x - x1)
Given: (0,2) and y = 3x + 2

When the line is perpendicular, flip the slope upside down and make it into its opposite ( - to +).

Slope: -1/3

y - 2 = -1/3(x - 0)
y - 2 = -1/3x + 0
+ 2 + 2
---------------------------
y = -1/3x + 2

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