The sum of the arithmetic series given is 2+5+8+ ... + 59
The first term is a₁ = 2 The common difference is d = 5-2 = 3 The n-th term is a₁ + (n-1)d Therefore the last term is given by 2 + 3(n-1) = 59 3(n-1) = 57 n-1 = 19 n = 20
The sum of n terms is [tex]S_{n} = \frac{n}{2}(a_{1} + a_{n} ) [/tex]
Therefore the sum of the series is [tex] \frac{20}{2}(2+59) = 610 [/tex]
