Respuesta :

Hosein

[tex] \sqrt{16 + {(7 - y)}^{2} } = 6 \\ 16 + {(7 - y)}^{2} = 36 \\ {(7 - y)}^{2} = 20[/tex]
[tex]7 - y = \sqrt{20} > > y = 7 - \sqrt{20} \\ 7 - y = - \sqrt{20} > > y = 7 + \sqrt{20} [/tex]